[ZendTo] Error after upgrade

Dale E. Qualls deq at pattishall.com
Wed Feb 1 14:35:24 GMT 2017


I know I'm on 5.2.17, I checked that out yesterday and did some googling and it said that the ?: was fine after 5.2 but the older version is probably the issue.  Will anything break if I upgrade to 5.3?

php --version
PHP 5.2.17 (cli) (built: Jan 11 2011 11:13:37)
Copyright (c) 1997-2010 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2010 Zend Technologies

md5sum /opt/zendto/lib/NSSUtils.php
e382d79b8aded31d177861a86f69738c  /opt/zendto/lib/NSSUtils.php

php -l /opt/zendto/lib/NSSUtils.php
No syntax errors detected in /opt/zendto/lib/NSSUtils.php

Thanks, Jules!!








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Dale E. Qualls
Director of Information Technology
Pattishall, McAuliffe, Newbury, Hilliard & Geraldson LLP
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From: zendto-bounces at zend.to [mailto:zendto-bounces at zend.to] On Behalf Of Jules
Sent: Wednesday, February 01, 2017 3:17 AM
To: ZendTo Users
Subject: Re: [ZendTo] Error after upgrade

Dale,

Please can you run 3 commands for me and send me the output of them:

php --version
md5sum /opt/zendto/lib/NSSUtils.php
php -l /opt/zendto/lib/NSSUtils.php

If you are running PHP earlier than 5.3, you will almost certainly get a syntax error of some sort on that line, as prior to 5.3 you couldn't skip the value between the "?" and the ":".

If that turns out to be the cause, replace that line with these 2:

$the_ip = filter_var($the_ip, FILTER_VALIDATE_IP);
$the_ip = $the_ip ? $the_ip : '0.0.0.0';

That should achieve the same thing, if my brain is attached correctly this morning.

Please do let me know how you get on.

Cheers,
Jules.
On 31/01/2017 16:49, Dale E. Qualls wrote:
I upgraded today (yum update zendto) and everything appeared to update normally.

Trying to open the site in the browser, I received this:

Parse error: syntax error, unexpected ';' in /opt/zendto/lib/NSSUtils.php on line 193

The only semicolon on that line is the one at the end:

/* Fetch the REMOTE_ADDR of the http connection, even through proxies */
function getClientIP()
{
  // Get the forwarded IP if it exists
  if ( isset($_SERVER['HTTP_CLIENT_IP']) && array_key_exists('HTTP_CLIENT_IP', $_SERVER) ) {
    $the_ip = $_SERVER['HTTP_CLIENT_IP'];
  } elseif ( isset($_SERVER['HTTP_X_FORWARDED_FOR']) && array_key_exists('HTTP_X_FORWARDED_FOR', $_SERVER )) {
    $the_ips = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
    $the_ip = trim($the_ips[0]);
  } else {
    $the_ip = $_SERVER['REMOTE_ADDR'];
  }

  // Now validate it
  $the_ip = filter_var($the_ip, FILTER_VALIDATE_IP) ?: '0.0.0.0';    <-------------THIS IS LINE 193

  return $the_ip;
}

Any thoughts or suggestions?







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Dale E. Qualls
Director of Information Technology
Pattishall, McAuliffe, Newbury, Hilliard & Geraldson LLP
200 South Wacker Drive, Suite 2900
Chicago, IL 60606-5896
Direct: (312) 554-7979 Main: (312) 554-8000 Fax: (312) 554-8015
deq at pattishall.com<mailto:deq at pattishall.com> www.pattishall.com<http://www.pattishall.com> Follow us on Twitter<http://www.twitter.com/Pattishall>



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Jules



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